The LeetCode challenge I undertook today was to count the pairs of numbers in an array whose sum is less than a given target value. This problem tested my ability to devise an efficient algorithm to find the pairs and successfully implement it using C++.
Approach: Using Two Pointers
I approached the problem using the two-pointer technique. By sorting the array first, I placed two pointers at the beginning and end of the array. As I iterated through the array, I calculated the sum of the elements pointed to by the two pointers. If the sum was less than the target, I could count all the pairs between the two pointers, as they would satisfy the condition.
Day 36 has been a productive and rewarding day of my DSA C++ journey. Tackling the LeetCode problem "Count Pairs Whose Sum is Less than Target" deepened my understanding of algorithmic techniques and C++ implementation. As I continue to conquer challenges like these, I am growing not only as a programmer but also as a problem solver. Stay tuned for more exciting adventures ahead! Happy coding, everyone!